(z^2+2z+5)/(2z^2+1)=1

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Solution for (z^2+2z+5)/(2z^2+1)=1 equation: 



(z^2+2z+5)/(2z^2+1)=1

We move all terms to the left:

(z^2+2z+5)/(2z^2+1)-(1)=0



Domain of the equation: (2z^2+1)!=0

We move all terms containing z to the left, all other terms to the right

2z^2!=-1

z^2!=-1/2

z^2!=√-1/2

z!=NAN

z∈R



We multiply all the terms by the denominator


(z^2+2z+5)-1*(2z^2+1)=0

We get rid of parentheses

z^2+2z-1*(2z^2+1)+5=0

We move all terms containing z to the left, all other terms to the right

z^2+2z-1*(2z^2+1)=-5

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